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1037: 50 Residue Symmetric Pentamer Design

Closed since about 11 years ago

Intermediate Overall Design

Summary

Created
January 14, 2015
Expires
Max points
100
Description

This puzzle again uses separate "Core Existence" filters for the monomer unit and the symmetric complex. Click the "Show" checkbox beneath the Core Existence filter to see which residues have been identified as Core (orange), Boundary (green), or Surface (blue). There are several other filters in effect; see the puzzle comments for details. The Baker Lab will run folding predictions on your solutions for this puzzle, and those that perform well will be synthesized in the lab. Remember, you can use the Upload for Scientists button for up to 5 designs that you want us to look at, even if they are not the best-scoring solutions!

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  1. Avatar for dettingen 171. dettingen Lv 1 1 pt. 0
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  3. Avatar for crazo 173. crazo Lv 1 1 pt. 0
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  5. Avatar for keyvan1821 175. keyvan1821 Lv 1 1 pt. 0
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  7. Avatar for rol 177. rol Lv 1 1 pt. 0
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  9. Avatar for crawlee34225 179. crawlee34225 Lv 1 1 pt. 0
  10. Avatar for packer 180. packer Lv 1 1 pt. 0

Comments

bkoep Staff Lv 1

Residue IE Score: Monitors that all PHE, TYR, and TRP residues are scoring well.

Core Existence: Monomer: Ensures that at least 20% of the residues are buried in the core of the monomer unit.

Core Existence: Complex: Ensures that at least 35% of the residues are buried in the core of the entire complex (including the interface between monomer units).

Fragment Score: Scans for parts of your design that are unlikely to fold up naturally. Use Rebuild and Remix tools to fix these regions of your design!

Secondary Structure Design: Penalizes GLY, ALA, and PRO residues in helices and sheets.

bkoep Staff Lv 1

In general, Foldit score does increase with the number of residues in a design, but "symmetric residues" do not contribute in this case. We expect designs in this puzzle to score similarly to a 50 residue monomer, with the addition of the interface points for a single monomer subunit.

Bruno Kestemont Lv 1

I found the formula was like 8000 + net filters+ about [13-25] * monomer number of residues * symmetry

That would make a potential of about
11720 to 14720 pts for this one

11523 seems quite low indeed, but I think it's much more difficult to get higher scores with the many conditions that are present now.

(In the past, you had more freedom to find unrealistic high scoring solutions).